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This is a 5V 8-Channel Relay interface board, Be able to control various appliances, and other equipments with large current. It can be controlled directly by Microcontroller(Arduino , 8051, AVR, PIC, DSP, ARM, ARM, MSP430, TTL logic).
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Pretty amateur with electronics here. I am working on a project where I want to detect an AC signal. I started by modifying a circuit I found online, the concept makes sense, I think the issue is in the details. Right now I am using a bridge rectifier and then a 15V zener diode (to block any noise). After that I have some current limiting resistors and an opto-isolator that switches a higher power circuit. The problem is that I don't think I am getting a strong enough signal at the opto-isolator for it to operate. I hooked it up to a scope and when I applied the input I was getting a full wave rectified sine wave from around 0-1 volts at the opto isolator. I think I need to do some or all of the following: -Add a smoothing cap across the rectifier to smooth out the waveform a bit and allow the isolator to trigger for longer periods of time instead of just near peaks. I'm not sure how to size this capacitor though. -Use a lower voltage zener diode, maybe a 12v -Use less resistance for the current limiter I'm using a 4N27 opto-isolator, I am not savvy enough to be able to tell from the specs what input voltage is required to close the "relay side" of the IC, or how much is too much for it. Here's the basic circuit I am using: http://www.epanorama.net/circuits/telephone_ringer.html It's the second one on that page, with only one zener. I believe the diode is used to prevent random low voltage variations on the line from triggering the isolator. Also, I am only seeing a signal of around 25VAC @ 20hz, where I think this circuit was built for a 90VAC signal.
And got the following answer:
I'd need to see the circuit. for example, what is between the rectifier and the opto? And, yes, you need a cap to smooth out that ripple, the opto would be turning on and off due to that. What is the purpose of the zener, and where is it in the circuit? The 4N27 has a low gain, 0.1, so if the input current is 10 mA, you will get only 1 mA output. It's purpose is isolation, not gain. You may need a transistor on the output circuit to drive the relay. But your real problem, you state "I am not savvy enough". For example a Opto input is current driven, not voltage driven. so asking for the input voltage doesn't mean much. Start off by reading the datasheet for the opto. Any terms you don't understand, research. You can't use a part unless you understand it.
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