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all transistor data sheet pdf
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all transistor data sheet pdf
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Maria asked What prevents joule thiefs from operating at input voltages less than 0.3 volts? Is it the transistor?
I know that joule thiefs can operate at input voltages of 0.3 volts, but why cant they operate at input voltages of less than 0.3 volts? Is the joule thiefs capability of utilizing lower amounts of energy limited by the transistor? i.e. the transistor cannot operate at voltages of less than 0.3 volts? Or is it something else? Please be very specific, im trying to understand why this is. Thanks!!
And got the following answer:
The limitation is due to the base-emitter voltage being too low to cause the transistor to turn on with sufficient current gain to form an oscillator. Take a look at Figure 1, and memorize the terminals "collector", "base", and "emitter", because I am going to use those names: http://www.nxp.com/documents/data_sheet/BC549_550.pdf The base-emitter junction behaves like a silicon diode, where (positive) current enters the base and leaves the emitter. Let's call this "base current" or Ib. The diode develops a forward voltage drop that increases as current is increased, kind of like a resistor but very non-linear (does *not* follow Ohm's Law, which states that for a pure resistor, the increase in voltage is linear with current). When sufficient base current is injected into the transistor, transistor action starts, which allows current to enter the collector and leave the emitter. Let's call this "collector current" or Ic. The amount of collector current that flows depends upon the amount of base current there is. In the normal range, the transistor will exhibit current gain. The BC549 is spec'd at typically a gain (hFE) of 520 when the collector current Ic is 2mA (and the collector-emiter voltage VBE is 5.0V), meaning that only 3.85 microamps of base current is required to allow the 2mA of collector current to flow. This specification shows up in the table titled "Characteristics" on page 3, symble hFE dc current gain.: http://www.nxp.com/documents/data_sheet/BC549_550.pdf In order for this circuit to work, there has to be sufficient current gain so that the circuit will oscillate. As the base-emitter voltage VBE drops toward 3.0V, the base current also drops, and the current gain decreases to the point where the circuit stops oscillating. At that point the boost ceases and no more power can be extracted from the battery. Note in the Characteristics table on page 3, that the normal range for VBE is 0.58 to 0.70V for an Ic of 2.0mA. So by running this circuit down to VBE=0.30V, it has fallen way below the normal operating range. Figure 2 shows that the dc current gain is non-linear with IC on the high end of IC. The chart doesn't go to the left far enough to show that the gain also falls of on the low end, but it does.
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